What are the slope and y-intercept of the line y = -2x + 5?

What are the slope and y-intercept of the line y = -2x + 5?

• A. Slope 2, y-intercept 5
• B. Slope -2, y-intercept 5
• C. Slope 0, y-intercept 5
• D. Slope -2, y-intercept -5

Answer: (B)

In this line, the slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept—the value of y when x is 0. Here, the coefficient of x is -2, so the slope is -2. When x = 0, y = -2(0) + 5 = 5, so the line crosses the y-axis at 5, which is the y-intercept. That gives a line that falls as x increases (negative slope) and passes through (0, 5). So the slope is -2 and the y-intercept is 5. If the slope were positive, the line would rise as x increases; if it were 0, it would be horizontal; if the intercept were -5, it would cross the y-axis at -5.

In this line, the slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept—the value of y when x is 0. Here, the coefficient of x is -2, so the slope is -2. When x = 0, y = -2(0) + 5 = 5, so the line crosses the y-axis at 5, which is the y-intercept. That gives a line that falls as x increases (negative slope) and passes through (0, 5). So the slope is -2 and the y-intercept is 5. If the slope were positive, the line would rise as x increases; if it were 0, it would be horizontal; if the intercept were -5, it would cross the y-axis at -5.